Algebraic Identity (a+b)^3
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Find the cube of x+2y.
x3+8y3+6x2y+12xy2
x3+8y3+6x2y−12xy2
x3+8y3+12x2y+6xy2
x3+8y3−6x2y+12xy2
Using special products, simplify :
If a+1a=3, then find the value of (a2+1a2)(a3+1a3)
112
123
125
126
Find the cube of x+1x
x3+1x3+3x+3x
x3+1x3+3x+3x2
x3+1x3+3x2+3x
x3+1x3+3x2+3x2
(a+b)3−(a−b)3 =________
b3+3a2b
2(b3+3a2b)
2(a3+3ab2)
0
The cube of xy−1(xy)2=
x3y3−1x6y6−3+3xy
x3y3−1x6y6−3+3x2y2
x3y3−1x6y6−3+3x3y3
x3y3−1x3y3−3+3x3y3
Find the product of (2x−3y) and (4x2+9y2+6xy).
8x3−27y3
2x3−3y3
(2x−3y)3
(8x−27y)3
(1+2x)3
The value of (2x+3y)3 is __________.
8x3+27y3+36x2y+54xy2
8x3−27y2−36x2y+54xy2
8x3+36y3+36x2y+54xy2
18x3+27y3+36x2y+54xy2
(i) (4y2−9x2)(16y4+36x2y2+81x4)
(2x+1x)
2a+12a;(a≠0)
The power of in
Expand the following identity.
(2x+1)3
8x3−1+12x2+6x
8x3−1−12x2+6x
8x3+1+12x2+6x
8x3+1+12x2−6x
- 4a3+14a3+4a+82a
- 8a3−18a3−6a−32a
- 8a3+18a3+6a+32a
- 16a3−18a3+6a−82a
- 125a3−225a2b−135ab2−27b3
- 125a3+27b3+225a2b+135ab2
- 125a3+125a2b+135ab2−27b3
- 125a3−225a2b−135ab2−27b3
Find the cube of x+2y.
x3+8y3+6x2y+12xy2
x3+8y3+6x2y−12xy2
x3+8y3+12x2y+6xy2
x3+8y3−6x2y+12xy2
If a+1a=3, then find the value of (a2+1a2)(a3+1a3)
123
125
126
112
- 4n2+4n−1
- 4n2−4n+1
- 4n2+4n+1
- 4n2−4n−1